January 26, 2018
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Tags:- PHP
Bellow code is used for the same
$date1 = date(‘Y-m-d’); $date2 = ‘2006-08-15’; $days = (strtotime($date1) – strtotime($date2)) / (60 * 60 * 24); echo $days;
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What are the errors in below code? What will be output and how can you fix it?
Explain Global, Local and Nonlocal variables.
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